1-9.  A bar is subject to an axial force P ~ N(1000, 50²) kN. If E = 120 GPa and v = 0.3, determine the distributions of the final lengths of sides L and b.

Solution

Solving for the new length L

Thus

 = 2.003 m                                  

 = 1.667∙10⁴ m                         

Then

 m                                           

Solving for the new width b

Thus

 = 49.975 mm                                    

 = 0.00125 mm                     

Then

 mm