2. A load follows a normal distribution and is suspended from the hook. The load is supported by the cable AD lies in the x-y plane and cable AC lies in the x-z plane. The spring has a stiffness . Determine the distribution of the tension in the cables and the distribution of the stretch of the spring for equilibrium.

Solution

Equations of equilibrium

We already know , and then we solve the above equations for the distribution of

So the distribution of the force in cable AC is .        Ans.

Then the same for , and finally

Ans.

Ans.

The distribution of the stretch of the spring is therefore

Thus, the distribution of the stretch of the spring is .       Ans.